Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.3 - Adding and Subtracting Algebraic Fractions - Problem Set 7.3: 76

Answer

$\frac{15x-9}{(x-2)(x+1)}$

Work Step by Step

By inspection, we see that the LCM of the denominators is $(x-2)(x+1)$. Therefore, we create a common denominator using this LCM and obtain: $\frac{7}{x-2}+\frac{8}{x+1}$ =$\frac{7(x+1)+8(x-2)}{(x-2)(x+1)}$ =$\frac{7x+7+8x-16}{(x-2)(x+1)}$ =$\frac{15x-9}{(x-2)(x+1)}$
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