Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.3 - Adding and Subtracting Algebraic Fractions - Problem Set 7.3 - Page 292: 53

Answer

$\frac{9n-14}{18}$

Work Step by Step

By inspection, we see that the LCM of the denominators is $18$. Therefore, we create a common denominator using this LCM and obtain: $\frac{4n-3}{6}-\frac{3n+5}{18}$ =$\frac{3(4n-3)-1(3n+5)}{18}$ =$\frac{12n-9-3n-5}{18}$ =$\frac{12n-3n-9-5}{18}$ =$\frac{9n-14}{18}$
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