Answer
$4n(n+5)(n-5)$
Work Step by Step
Since $4n$ is common to both the terms of the equation, we take it out as a common factor:
$4n^{3}-100n=4n(n^{2}-25)$
We simplify the expression further using the rule $a^{2}-b^{2}=(a+b)(a-b)$:
$4n(n^{2}-25)=4n(n^{2}-5^{2})=4n(n+5)(n-5)$
