## Elementary Algebra

The dimensions of the square is $3 \times 3$ inches. The dimensions of the rectangle is $6 \times 3$ inches.
Let $a =$ area of the rectangle Let $x =$ area of the square Let $p =$ width of rectangle and length of square $a = 2x$ $2x = 2p^{2}$ $a = 6 \times p$ $a = 2p^{2}$ $6p = 2p^{2}$ $6p - 2p^{2}= 0$ $2p(3 - p) = 0$ $p = 0, 3$ Recall, 0 is not a valid value for length. Therefore, the dimensions of the square are $3 \times 3$ inches. Therefore, the dimensions of the rectangle are $6 \times 3$ inches.