Answer
$(2n-1)(3n-4)$
Work Step by Step
Using factoring by grouping, the factored form of the given expression, $
6n^2-3n-8n+4
,$ is
\begin{array}{l}\require{cancel}
(6n^2-3n)-(8n-4)
\\\\=
3n(2n-1)-4(2n-1)
\\\\=
(2n-1)(3n-4)
.\end{array}
Elementary Algebra
by Kaufmann, Jerome; Schwitters, Karen;
Published by
Cengage Learning
ISBN 10:
1285194055
ISBN 13:
978-1-28519-405-9
Chapter 6 - Factoring, Solving Equations, and Problem Solving - 6.1 - Factoring by Using the Distributive Property - Problem Set 6.1 - Page 243: 59
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