# Chapter 6 - Factoring, Solving Equations, and Problem Solving - 6.1 - Factoring by Using the Distributive Property - Problem Set 6.1 - Page 243: 59

$(2n-1)(3n-4)$

#### Work Step by Step

Using factoring by grouping, the factored form of the given expression, $6n^2-3n-8n+4 ,$ is \begin{array}{l}\require{cancel} (6n^2-3n)-(8n-4) \\\\= 3n(2n-1)-4(2n-1) \\\\= (2n-1)(3n-4) .\end{array}

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