## Elementary Algebra

$x=\{ 0,12 \}$
Factoring out the $GCF= x ,$ the factored form of the given expression, $x^2-12x=0 ,$ is \begin{array}{l}\require{cancel} x(x-12) =0 .\end{array} Equating each factor to zero, wo obtain: \begin{array}{l}\require{cancel} x=0 ,\\\\\text{OR}\\\\ x-12=0 \\\\ x=12 .\end{array} Hence, the solution set is $x=\{ 0,12 \} .$