## Elementary Algebra

$x = \frac{2}{3}, 7$
There are two ways to solve for $x$: 1) Expand and simplify $x(3x -2) - 7(3x-2) = 0$ $3x^{2} - 2x - 21x + 14 = 0$ $3x^{2}-23x+14$ 2) Simply solve for $x$ $(x-7)(3x-2) = 0$ $x = \frac{2}{3}, 7$