Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 4 - Proportions, Percents, and Solving Inequalities - Chapters 1-4 Cumulative Review Problem Set: 33

Answer

n = $\frac{34}{3}$ $\approx$ 11.3

Work Step by Step

$\frac{2n-1}{5}$ - $\frac{n+2}{4}$ = 1 We need to change the denominator of all fractions to 20. $\frac{2n-1}{5}$ $\times$ $\frac{4}{4}$- $\frac{n+2}{4}$ $\times$ $\frac{5}{5}$= 1 $\times$ $\frac{20}{20}$ $\frac{(2n-1)\times4}{20}$ - $\frac{(n+2)\times5}{20}$ = $\frac{20}{20}$ Multiply both sides by 20. (2n-1) $\times$ 4 - (n+2) $\times$ 5 = 20 Use the distributive property. 8n - 4 -5n - 10 = 20 3n - 14 = 20 3n = 34 Divide both sides by 3. n = $\frac{34}{3}$ $\approx$ 11.3
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