Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 4 - Proportions, Percents, and Solving Inequalities - Chapters 1-4 Cumulative Review Problem Set - Page 186: 31


x = 12.5

Work Step by Step

$\frac{2}{5}$x - $\frac{1}{3}$ = $\frac{1}{3}$x + $\frac{1}{2}$ In order to solve for x, we first need to get all of the terms with an x in them on the same side of the equation and move all the other terms to the other side of the equation. $\frac{2}{5}$x - $\frac{1}{3}$x = $\frac{1}{2}$ + $\frac{1}{3}$ We need to change the denominator of each fraction to 15. $\frac{2}{5}$x $\times$ $\frac{3}{3}$- $\frac{1}{3}$x $\times$ $\frac{5}{5}$ = $\frac{1}{2}$ $\times$ $\frac{7.5}{7.5}$+ $\frac{1}{3}$ $\times$ $\frac{5}{5}$ $\frac{6}{15}$x - $\frac{5}{15}$x = $\frac{7.5}{15}$ + $\frac{5}{15}$ $\frac{x}{15}$ = $\frac{12.5}{15}$ Multiply both sides by 15. x = 12.5
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