## Elementary Algebra

Published by Cengage Learning

# Chapter 4 - Proportions, Percents, and Solving Inequalities - Chapters 1-4 Cumulative Review Problem Set - Page 186: 32

#### Answer

t = $\frac{-4}{7}$ $\approx$ -0.57

#### Work Step by Step

$\frac{t-2}{4}$ + $\frac{t+3}{3}$ = $\frac{1}{6}$ We need to change the denominator of each fraction to 12. $\frac{t-2}{4}$ $\times$ $\frac{3}{3}$+ $\frac{t+3}{3}$ $\times$ $\frac{4}{4}$ = $\frac{1}{6}$ $\times$ $\frac{2}{2}$ $\frac{(t-2) \times3}{12}$ + $\frac{(t+3) \times 4}{12}$ = $\frac{2}{12}$ Multiply both sides by 12. (t-2) $\times$ 3 + (t+3) $\times$ 4 = 2 Use the distributive property. 3t - 6 + 4t + 12 = 2 7t + 6 = 2 7t = -4 Divide both sides by 7. t = $\frac{-4}{7}$ $\approx$ -0.57

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