Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 4 - Proportions, Percents, and Solving Inequalities - Chapters 1-4 Cumulative Review Problem Set - Page 186: 16



Work Step by Step

$\frac{3}{4}$n - $\frac{1}{3}$n + $\frac{5}{6}$n = We must convert the denominators of each fraction to 12. $\frac{3}{4}$n $\times$ $\frac{3}{3}$ - $\frac{1}{3}$n $\times$ $\frac{4}{4}$+ $\frac{5}{6}$n $\times$ $\frac{2}{2}$= $\frac{9}{12}$n - $\frac{4}{12}$n + $\frac{10}{12}$n = $\frac{15}{12}$n We then substitute n = -$\frac{2}{3}$ into the expression. $\frac{15}{12}$ $\times$ -$\frac{2}{3}$ = -$\frac{30}{36}$ = -$\frac{5}{6}$
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