Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 4 - Proportions, Percents, and Solving Inequalities - Chapters 1-4 Cumulative Review Problem Set: 25

Answer

$\frac{25}{36}$

Work Step by Step

First, we will simplify the expression within the parenthesis by finding the least common denominator: $(\frac{1}{2}+\frac{1}{3})^{2}$ =$(\frac{1(3)+1(2)}{6})^{2}$ =$(\frac{3+2}{6})^{2}$ =$(\frac{5}{6})^{2}$ Next, we raise both the numerator and the denominator to the power of $2$ and simplify: $(\frac{5}{6})^{2}=\frac{5^{2}}{6^{2}}=\frac{5\times5}{6\times6}=\frac{25}{36}$
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