Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 4 - Proportions, Percents, and Solving Inequalities - 4.1 - Ratios and Proportions - Problem Set 4.1: 61


33.3333 pounds, or approximately 33 pounds, of fertilizer are needed for 2500 square feet of lawn.

Work Step by Step

Let X represent the amount of fertilizer needed for 2500 square feet. Now, let’s set up a proportion in which one ratio compares the amounts of fertilizer, and the other ratio compares the surfaces covered. So, $\frac{20}{X}$ = $\frac{1500}{2500}$. We cross multiply to obtain: 20 $\times$ 2500 = X $\times$ 1500 50000 = 1500X X = 33.3333
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