Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 4 - Proportions, Percents, and Solving Inequalities - 4.1 - Ratios and Proportions - Problem Set 4.1: 59

Answer

7.5 pounds of salt are needed for 25 gallons of water.

Work Step by Step

Let X represent the pounds of salt needed for 25 gallons of water. Now, let’s set up a proportion in which one ratio compares the amounts of salt and the other ratio compares the amounts of water. So, $\frac{3}{X}$ = $\frac{10}{25}$ To solve this equation, we equate the cross products. 3 $\times$ 25 = X $\times$ 10. 75 = 10X Divide both sides by 10. X = 7.5 7.5 pounds of salt are needed for 25 gallons of water.
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