Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 4 - Proportions, Percents, and Solving Inequalities - 4.1 - Ratios and Proportions - Problem Set 4.1 - Page 149: 54



Work Step by Step

Using cross-multiplication, the value of the variable that satisfies the given equation, $ \dfrac{4(x+3)}{7}=\dfrac{2(x-6)}{5} ,$ is \begin{array}{l}\require{cancel} 4(5)(x+3)=2(7)(x-6) \\\\ 20x+60=14x-84 \\\\ 20x-14x=-84-60 \\\\ 6x=-144 \\\\ x=-\dfrac{144}{6} \\\\ x=-24 .\end{array}
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