## Elementary Algebra

$h=6$
Multiplying both sides by the $LCD= 6 ,$ the value of the variable that satisfies the given equation, $\dfrac{h}{2}-\dfrac{h}{3}=1 ,$ is \begin{array}{l}\require{cancel} 3(h)-2(h)=6(1) \\\\ 3h-2h=6 \\\\ h=6 .\end{array}