Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 4 - Proportions, Percents, and Solving Inequalities - 4.1 - Ratios and Proportions - Problem Set 4.1 - Page 149: 34



Work Step by Step

Multiplying both sides by the $LCD= 30 ,$ the value of the variable that satisfies the given equation, $ \dfrac{x-2}{5}-\dfrac{x+3}{6}=-4 ,$ is \begin{array}{l}\require{cancel} 6(x-2)-5(x+3)=30(-4) \\\\ 6x-12-5x-15=-120 \\\\ 6x-5x=-120+12+15 \\\\ x=-93 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.