Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 3 - Equations and Problem Solving - 3.1 - Solving First-Degree Equations - Problem Set 3.1 - Page 100: 66



Work Step by Step

Multiplying both sides by the $LCD= 3 ,$ and using the properties of equality, the value of the variable that satisfies the given equation, $ -12n=\dfrac{8}{3} ,$ is \begin{array}{l}\require{cancel} 3(-12n)=1(8) \\\\ -36n=8 \\\\ n=\dfrac{8}{-36} \\\\ n=\dfrac{\cancel{4}\cdot2}{\cancel{4}\cdot(-9)} \\\\ n=\dfrac{2}{-9} \\\\ n=-\dfrac{2}{9} .\end{array}
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