# Chapter 3 - Equations and Problem Solving - 3.1 - Solving First-Degree Equations - Problem Set 3.1 - Page 100: 19

$y=-\dfrac{4}{15}$

#### Work Step by Step

Multiplying both sides of the equation by the least common multiple of the denominators, which is 15, and using the properties of equality, the value of the variable that satisfies the given equation, $y+\dfrac{3}{5}=\dfrac{1}{3} ,$ is \begin{array}{l}\require{cancel} 15\left( y+\dfrac{3}{5} \right)=\left( \dfrac{1}{3} \right)15 \\\\ 15(y)+3(3)=1(5) \\\\ 15y+9=5 \\\\ 15y=5-9 \\\\ 15y=-4 \\\\ y=-\dfrac{4}{15} .\end{array}

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