Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 3 - Equations and Problem Solving - 3.1 - Solving First-Degree Equations - Problem Set 3.1 - Page 100: 20



Work Step by Step

Multiplying both sides of the equation by the least common multiple of the denominators, which is 40, and using the properties of equality, the value of the variable that satisfies the given equation, $ x+\dfrac{5}{8}=\dfrac{2}{5} ,$ is \begin{array}{l}\require{cancel} 40\left( x+\dfrac{5}{8} \right)=\left( \dfrac{2}{5} \right)40 \\\\ 40(x)+5(5)=2(8) \\\\ 40x+25=16 \\\\ 40x=16-25 \\\\ 40x=-9 \\\\ x=-\dfrac{9}{40} .\end{array}
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