Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 3 - Equations and Problem Solving - 3.1 - Solving First-Degree Equations - Problem Set 3.1 - Page 100: 64



Work Step by Step

Multiplying both sides by the $LCD= 4 ,$ and using the properties of equality, the value of the variable that satisfies the given equation, $ -6n=\dfrac{3}{4} ,$ is \begin{array}{l}\require{cancel} 4(-6n)=1(3) \\\\ -24n=3 \\\\ n=\dfrac{3}{-24} \\\\ n=\dfrac{\cancel{3}}{\cancel{3}\cdot(-8)} \\\\ n=\dfrac{1}{-8} \\\\ n=-\dfrac{1}{8} .\end{array}
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