Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 3 - Equations and Problem Solving - 3.1 - Solving First-Degree Equations - Problem Set 3.1 - Page 100: 52



Work Step by Step

Multiplying both sides of the equation by $ \dfrac{7}{6} $ (which is the reciprocal of 6/7) and using the properties of equality, the value of the variable that satisfies the given equation, $ \dfrac{6}{7}n=-\dfrac{3}{8} ,$ is \begin{array}{l}\require{cancel} n=-\dfrac{3}{8}\cdot\dfrac{7}{6} \\\\ n=-\dfrac{\cancel{3}}{8}\cdot\dfrac{7}{\cancel{3}\cdot2} \\\\ n=-\dfrac{7}{16} .\end{array}
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