Answer
$-6+10i$
Work Step by Step
(Recall, we must distribute the negative to everything in the second and third sets of parenthesis.)
Adding the real terms together and the imaginary terms together, we obtain:
$(-4+i)-(-4-i)-(6-8i)$
=$-4+i+4+i-6+8i$
=$(-4+4-6)+(i+i+8i)$
=$-6+10i$
