Answer
(2,1,3)
Work Step by Step
In order to solve systems of three linear equations, we multiply the first and second equation by values that will cancel out a variable when they are added. Thus, we multiply the first equation by 1 and the second equation by 1 and add to obtain:
$3x+5y = 11$
We now multiply the first and third equation by values that will cancel out a variable when they are added. Thus, we multiply the first equation by 2 and the third equation by one and add to obtain:
$ 7x + 7y = 21 $
Plugging $x =- 5/3y +11/3$ into this equation, we obtain:
$-4.67y +25.67 = 21 \\ y =1 $
Now, we plug this value into one of the equations that only has x and y in them to find:
$ x = 2$
Finally, we plug the values of x and y into the first equation listed in the book to find:
$ z = 3$
