Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - Chapter 11 Review Problem Set: 39

Answer

$8x^{3}$

Work Step by Step

Using the rule $\frac{a^{m}}{a^{n}}=a^{m-n}$, we obtain: $(\frac{6x^{\frac{2}{7}}}{3x^{-\frac{5}{7}}})^{3}$ =$(\frac{6}{3}\times\frac{x^{\frac{2}{7}}}{x^{-\frac{5}{7}}})^{3}$ =$(2\times x^{\frac{2}{7}-(-\frac{5}{7})})^{3}$ =$(2\times x^{\frac{2}{7}+\frac{5}{7}})^{3}$ =$(2\times x^{\frac{2+5}{7}})^{3}$ =$(2\times x^{\frac{7}{7}})^{3}$ =$(2x^{1})^{3}$ =$2^{3}x^{1\times3}$ =$8x^{3}$
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