Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - Chapter 11 Review Problem Set - Page 520: 38



Work Step by Step

Using the rule $\frac{a^{m}}{a^{n}}=a^{m-n}$, we obtain: $\frac{64n^{\frac{5}{8}}}{16n^{\frac{7}{8}}}$ =$\frac{64}{16}\times\frac{n^{\frac{5}{8}}}{n^{\frac{7}{8}}}$ =$4\times n^{\frac{5}{8}-\frac{7}{8}}$ =$4\times n^{\frac{5(1)-7(1)}{8}}$ =$4\times n^{\frac{5-7}{8}}$ =$4\times n^{\frac{-2}{8}}$ =$4n^{-\frac{1}{4}}$ =$\frac{4}{n^{\frac{1}{4}}}$
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