## Elementary Algebra

$27xy^{2}$
Raising each term in the expression to the power of 3 and then simplifying, we obtain: $(3x^{\frac{1}{3}}y^{\frac{2}{3}})^{3}$ $=(3)^{3}\times (x^{\frac{1}{3}})^{3}\times(y^{\frac{2}{3}})^{3}$ $=27\times (x^{\frac{1}{3}\times3})\times(y^{\frac{2}{3}\times3})$ $=27\times (x^{1})\times(y^{2})$ $=27xy^{2}$