## Elementary Algebra

Published by Cengage Learning

# Chapter 10 - Quadratic Equations - 10.3 - Quadratic Formula - Problem Set 10.3 - Page 453: 12

#### Answer

No real number solutions

#### Work Step by Step

Step 1: Comparing $n^{2}+6n+11=0$ to the standard form of a quadratic equation $an^{2}+bn+c=0$, we obtain: $a=1$, $b=6$ and $c=11$ Step 2: The quadratic formula is: $x=\frac{-b \pm \sqrt {b^{2}-4ac}}{2a}$ Step 3: Substituting the values of a,b and c in the formula: $x=\frac{-(6) \pm \sqrt {(6)^{2}-4(1)(11)}}{2(1)}$ Step 4: $x=\frac{-6\pm \sqrt {36-44}}{2}$ Step 5: $x=\frac{-6 \pm \sqrt {-8}}{2}$ Since their are no real number solutions to $\sqrt {-8}$, there are no real number solutions to the equation.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.