Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.3 - Quadratic Formula - Problem Set 10.3 - Page 453: 14



Work Step by Step

Step 1: $x^{2}+8x=0$ can also be written as $x^{2}+8x+0=0$. Comparing $x^{2}=8x+0=0$ to the standard form of a quadratic equation, $ax^{2}+bx+c=0$, we obtain: $a=1$, $b=8$ and $c=0$ Step 2: The quadratic formula is: $x=\frac{-b \pm \sqrt {b^{2}-4ac}}{2a}$ Step 3: Substituting the values of a,b, and c in the formula, we obtain: $x=\frac{-(8) \pm \sqrt {(8)^{2}-4(1)(0)}}{2(1)}$ Step 4: $x=\frac{-8 \pm \sqrt {64-0}}{2}$ Step 5: $x=\frac{-8 \pm \sqrt {64}}{2}$ Step 6: $x=\frac{-8 \pm 8}{2}$ Step 7: $x=\frac{-8+8}{2}$ or $x=\frac{-8-8}{2}$ Step 8: $x=\frac{0}{2}$ or $x=\frac{-16}{2}$ Step 9: $x=0$ or $x=-8$ Step 10: Therefore, the solution set is {$-8,0$}.
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