Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - 10.3 - Quadratic Formula - Problem Set 10.3: 10

Answer

{$4$}

Work Step by Step

Step 1: Comparing $x^{2}-8x+16=0$ to the standard form of a quadratic equation $ax^{2}+bx+c=0$; $a=1$, $b=-8$ and $c=16$ Step 2: The quadratic formula is: $x=\frac{-b \pm \sqrt {b^{2}-4ac}}{2a}$ Step 3: Substituting the values of a, b and c in the formula: $x=\frac{-(-8) \pm \sqrt {(-8)^{2}-4(1)(16)}}{2(1)}$ Step 4: $x=\frac{8 \pm \sqrt {64-64}}{2}$ Step 5: $x=\frac{8 \pm \sqrt {0}}{2}$ Step 6: $x=\frac{8}{2}$ Step 7: $x=4$ Step 8: Therefore, the solution set is {$4$}.
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