Answer
No.
Work Step by Step
We know that for a matrix
\[
\left[\begin{array}{rrr}
a & b & c \\
d &e & f \\
g &h & i \\
\end{array} \right]
\]
the determinant, $D=a(ei-fh)-b(di-fg)+c(dh-eg).$
Hence here $D=2(-9-5)-(-1)(9-5)+4(3-(-3))=2(-14)+1(4)+4(6)=-28+4+24=0$.
thus they are coplanar, they don't span the space.