Answer
Yes.
Work Step by Step
We know that for a matrix
\[
\left[\begin{array}{rrr}
a & b & c \\
d &e & f \\
g &h & i \\
\end{array} \right]
\]
the determinant, $D=a(ei-fh)-b(di-fg)+c(dh-eg).$
Hence here $D=1(5-(-6))-(-1)(2-12)+1(-4-20)=1(11)+1(-10)+1(-24)=11-10-24=-23\ne0$
Thus they are not coplanar, they span the space.
