Answer
Yes.
Work Step by Step
We know that for a matrix
\[
\left[\begin{array}{rrr}
a & b & c \\
d &e & f \\
g &h & i \\
\end{array} \right]
\]
the determinant, $D=a(ei-fh)-b(di-fg)+c(dh-eg).$
Hence here $D=1(6-(-1))-(-2)(4-4)+1(-2-12)=1(7)+2(0)+1(-14)=7-0-14=-7\ne0$, thus they are not coplanar, thus they span the space.