Answer
No.
Work Step by Step
We know that for a matrix
\[
\left[\begin{array}{rrr}
a & b & c \\
d &e & f \\
g &h & i \\
\end{array} \right]
\]
the determinant, $D=a(ei-fh)-b(di-fg)+c(dh-eg).$
Hence here $D=1(45-48)-2(36-42)+3(32-35)=1(-3)-2(-6)+3(-3)=-3+12-9=0$, thus they are coplanar, thus they don't span the space.