Answer
$z=(\frac{-13}{2}-\frac{i}{2},\frac{-7}{2}+\frac{7i}{2})$
Work Step by Step
Given: $2iz=(1+i)x-2y$
Plug in the given values:
$2iz=(1+i)(-2+i,3i) -2(5,2-2i)$
$2iz=(-2+i-3i+i^2,3i+3i^2)-(10,4-4i)$
$2iz=(-2-2i-1,3i-3)-(10,4-4i)$
$2iz=(-13-i,-7+7i)$
Hence, $z=(\frac{-13}{2}-\frac{i}{2},\frac{-7}{2}+\frac{7i}{2})$
