Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 4 - Vector Spaces - 4.1 Vectors in Rn - Problems - Page 252: 10

Answer

Proof

Work Step by Step

To prove vectors in $\mathbf{R}^4$ satisfies associativity under addition Let $x=(x_1,x_2,x_3,x_4) \in \mathbf{R}^4$ $\;\;\;\;,y=(y_1,y_2,y_3,y_4) \in \mathbf{R}^4$ $\;\;\;\;,z=(z_1,z_2,z_3,z_4) \in \mathbf{R}^4$ Enough to show that $x+(y+z)=(x+y)+z$ Consider $x+(y+z)=(x_1,x_2,x_3,x_4)+[(y_1,y_2,y_3,y_4)+(z_1,z_2,z_3,z_4)]$ $x+(y+z)=(x_1,x_2,x_3,x_4)+(y_1+z_1,y_2+z_2,y_3+z_3,y_4+z_4)$ $x+(y+z)=(x_1+y_1+z_1,x_2+y_2+z_2,x_3+y_3+z_3,x_4+y_4+z_4)$ Because all $x_i , y_i , z_i$ are real numbers $\Rightarrow x+(y+z)=(x_1+y_1,x_2+y_2,x_3+y_3,x_4+y_4)+(z_1,z_2,z_3,z_4)$ $\Rightarrow x+(y+z)=(x+y)+z$ Hence vectors in $\mathbf{R}^4$ satisfies associativity under addition.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.