Answer
See below
Work Step by Step
Using the Convolution Theorem
$L[Fa(t)]=\int^{\infty}_0 e^{-st}fa(t)dt\\
=\int^{\infty}_0 e^{-st} f(t-a)dt\\
=\int^{\infty}_0 e^{-s(u+a)}f(u)du\\
=e^{-as}\int^{\infty}_0 e^{-su} f(u) du\\
=e^{-as} L[f]$
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Chapter 10 - The Laplace Transform and Some Elementary Applications - 10.10 Chapter Review - Additional Problems - Page 719: 29
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