Answer
See below.
Work Step by Step
We know that $i^2=-1$
$z_1z_2=(-1+3i)(2-i)=-2+i+6i+3=1+7i$
$z_1/z_2=\frac{-1+3i}{2-i}=\frac{(-1+3i)(2+i)}{(2-i)(2+i)}=\frac{-2-i+6i-3}{4+1}=\frac{-5+5i}{5}=-1+i$
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