Answer
$\overline{z}=3+4i$ and $|z|=5$.
Work Step by Step
Of a complex number $z=a+bi$, $\overline{z}=a-bi$ and $|z|=\sqrt{a^2+b^2}$
Hence here, $\overline{z}=3-(-4i)=3+4i$ and $|z|=\sqrt{3^2+(-4)^2}=\sqrt{25}=5$.
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Appendix A - Review of Complex Numbers - Exercises for A - Problems - Page 795: 2
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
