Answer
See below.
Work Step by Step
We know that $i^2=-1$
$z_1z_2=(1+i)(3+2i)=3+2i+3i+2i^2=3+5i-2=1+5i$
$z_1/z_2=\frac{1+i}{3+2i}=\frac{(1+i)(3-2i)}{(3+2i)(3-2i)}=\frac{3-2i+3i+2}{9+4}=\frac{5+i}{13}=5/13+i/13$
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Appendix A - Review of Complex Numbers - Exercises for A - Problems - Page 795: 6
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