Answer
See below.
Work Step by Step
We know that $i^2=-1$
$z_1z_2=(1-2i)(3+4i)=3+4i-6i+8=11-2i$
$z_1/z_2=\frac{1-2i}{3+4i}=\frac{(1-2i)(3-4i)}{(3+4i)(3-4i)}=\frac{3-4i-6i-8}{9+16}=\frac{-5-10i}{25}$
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