Answer
$\frac{1-13i}{10}$
Work Step by Step
We know that $i^2=-1$
$z_1z_2=(4-i)(1+3i)=4+12i-i+3=7+11i$
$z_1/z_2=\frac{4-i}{1+3i}=\frac{(4-i)(1-3i)}{(1+3i)(1-3i)}=\frac{4-12i-i-3}{1+9}=\frac{1-13i}{10}$
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Appendix A - Review of Complex Numbers - Exercises for A - Problems - Page 795: 9
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