College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.3 - Integer Exponents and Scientific Notation - P.3 Exercises: 50

Answer

$8 \frac{1}{3}$ minutes

Work Step by Step

We know from physics that speed is distance over time, $s=d/t$. Thus $t=d/s$: $t=d/s=\frac{9.3*10^{7} mi}{186000 mi/sec}=500 s$ Dividing by 60 (seconds/min), we get $8 \frac{1}{3}$ minutes.
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