College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.3 - Integer Exponents and Scientific Notation - P.3 Exercises: 44

Answer

$6.3*10^{38}$

Work Step by Step

$\frac{(73.1)(1.6341*10^{28})}{0.0000000019}=\frac{(7.31*10)(1.6341*10^{28})}{1.9*10^{-9}}=\frac{7.31*1.6341}{1.9}*10^{1+28--9}=6.286985*10^{38}\approx 6.3*10^{38}$
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