College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.3 - Integer Exponents and Scientific Notation - P.3 Exercises - Page 24: 45

Answer

$7.4*10^{-14}$

Work Step by Step

$\frac{(0.0000162)(0.01582)}{(594621000)(0.0058)}=\frac{(1.62*10^{-5})(1.582*10^{-2})}{(5.94621*10^{8})(5.8*10^{-3})}=\frac{1.62*1.582}{594621*5.8}*10^{-5-2-8+3}=0.07431103*10^{-12}\approx0.074*10^{-12}=7.4*10^{-14}$
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