College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.3 - Integer Exponents and Scientific Notation - P.3 Exercises: 46

Answer

$3.19*10^{-106}$

Work Step by Step

$\frac{(3.542*10^{-6})^{9}}{(5.05*10^{4})^{12}}=\frac{(3.542)^{9}*10^{-54}}{(5.05)^{12}*10^{48}}=\frac{87747.96}{275103767.10}*10^{-54-48}=3.189631*10^{-4}*10^{-102}=3.189631*10^{-106}\approx 3.19*10^{-106}$
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