College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 9, Counting and Probability - Section 9.1 - Counting - 9.1 Exercises: 9

Answer

$100$

Work Step by Step

RECALL: $P(n, r) = \dfrac{n!}{(n-r)!}$ Use the formula above to obtain: $P(100, 1) = \dfrac{100!}{(100-1)!} \\P(100, 1) = \dfrac{100!}{99!} \\P(100, 1) = \dfrac{100(99!)}{99!}$ Cancel the common factor $99!$ to obtain: $P(100, 1) = 100$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.