## College Algebra 7th Edition

$156,849$
RECALL: $C(n, r) = \dfrac{n!}{r!(n-r)!}$ Use the formula above to obtain: $C(99, 3) = \dfrac{99!}{3!(99-3)!} \\C(99, 3)) = \dfrac{99!}{3!(96!!)} \\C(99, 3) = \dfrac{99(98)(97)(96!)}{3\cdot2\cdot1 \cdot 96!}$ Cancel the common factors to obtain: $\require{cancel} \\C(99, 3) = \dfrac{\cancel{99}33\cancel{(98}49)(97)\cancel{(96!)}}{\cancel{3}\cdot\cancel{2}\cdot1 \cdot \cancel{96!}} \\C(99, 3) = 156,849$