## College Algebra 7th Edition

$941,094$
RECALL: $P(n, r) = \dfrac{n!}{(n-r)!}$ Use the formula above to obtain: $P(99, 3) = \dfrac{99!}{(99-3)!} \\P(99, 3) = \dfrac{99!}{96!} \\P(99, 3) = \dfrac{99(98)(97)(96!)}{96!}$ Cancel the common factor $96!$ to obtain: $P(99, 3) = 99(98)(97) \\P(99, 3) = 941,094$