College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 9, Counting and Probability - Section 9.1 - Counting - 9.1 Exercises: 8

Answer

$30,240$

Work Step by Step

RECALL: $P(n, r) = \dfrac{n!}{(n-r)!}$ Use the formula above to obtain: $P(10, 5) = \dfrac{10!}{(10-5)!} \\P(10, 5) = \dfrac{10!}{5!} \\P(10, 5) = \dfrac{10(9)(8)(6)(5!)}{5!}$ Cancel the common factor $5!$ to obtain: $P(10, 5) = 10(9)(8)(7)(6) \\P(10, 5) = 30,420$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.